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#1 |
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queer femme-inist Relationship Status:
I'm lucky. ![]() Join Date: May 2010
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That is very like what my kids came up with as a group.
We had already talked about something our old textbook called the guessing game algorithm, and That algorithm is a lot like binary search. So they hypothesized that it would be efficient to divide the coins into groups, and They knew that it wouldn't be useful to divide the coins into two groups because The still wouldn't know which pile contained the counterfeit and They wanted something like a control, and Having the control changed the way they searched after the first few iterations. Anyway, it's worth noting that though the honors class came up with the naming system quickly and They were able to predict some of the sticky places, The other ninth grade class did very well at working together to solve this problem. |
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#2 |
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I was a history major......
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#3 |
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My idea:
#1-Divide the 100 coins into piles of 50. The heavier pile has the counterfeit. #2-Divide the heavier pile into piles of 25. The heavier pile has the counterfeit. #3-Divide the heavier pile into two piles of 12 (24). You hold one coin. IF the piles are equal, you have the counterfeit! IF they are unequal, you have a "normal" coin, and the heavier pile has the counterfeit. #4-Take the heavier pile (unless you were lucky above) of 12, and divide it into 6. The heavier pile has the counterfeit. #5-Take the heavier pile of 6 and divide into two groups of 3. The heavier pile has the counterfeit. #6-Take the heavier pile of 3, and put one coin on each pan. You hold one coin. IF the coins are equal-you have the counterfeit in your hand. IF the coins are unequal-that heavy coin is the counterfeit.
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The odds of going to the store for a loaf of bread and coming out with only a loaf of bread are three billion to one. ~Erma Bombeck
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#4 |
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Another please.
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